A number,x,equals 80 % of the average of 5, 7 | vedclass

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(C) The average of $5, 7, 14$ and $y$ is given by $\frac{5+7+14+y}{4} = \frac{26+y}{4}$.Given that $x$ is $80 \%$ of this average,we have $x = \frac{8

Vedclass · Accepted Answer

$39$

Vedclass · Answer

(C) The average of $5, 7, 14$ and $y$ is given by $\frac{5+7+14+y}{4} = \frac{26+y}{4}$.Given that $x$ is $80 \%$ of this average,we have $x = \frac{80}{100} 	imes \frac{26+y}{4} = \frac{4}{5} 	imes \frac{26+y}{4} = \frac{26+y}{5}$.So,$5x = 26+y$,which implies $y = 5x - 26$ ..... $(1)$.Also,the average of $x$ and $y$ is $26$,so $\frac{x+y}{2} = 26$,which means $x+y = 52$ ..... $(2)$.Substituting the value of $y$ from $(1)$ into $(2)$,we get $x + (5x - 26) = 52$.$6x = 78$,so $x = 13$.Substituting $x = 13$ into $(2)$,we get $13 + y = 52$,which gives $y = 52 - 13 = 39$.

$A$ number,$x$,equals $80 \%$ of the average of $5, 7, 14$ and a number $y$. If the average of $x$ and $y$ is $26$,then the value of $y$ is:

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