A pack of cards contains 4 aces,4 kings,4 que | vedclass

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(A) Total number of cards = $4 + 4 + 4 + 4 = 16$. Number of ways to draw $2$ cards from $16$ is $^{16}C_2 = \frac{16 	imes 15}{2 	imes 1} = 120$. Nu

Vedclass · Accepted Answer

$\frac{9}{20}$

Vedclass · Answer

(A) Total number of cards = $4 + 4 + 4 + 4 = 16$. Number of ways to draw $2$ cards from $16$ is $^{16}C_2 = \frac{16 	imes 15}{2 	imes 1} = 120$. Number of cards that are not aces = $16 - 4 = 12$. Number of ways to draw $2$ cards such that none of them is an ace is $^{12}C_2 = \frac{12 	imes 11}{2 	imes 1} = 66$. Probability of drawing no ace = $\frac{66}{120} = \frac{11}{20}$. Required probability of drawing at least one ace = $1 - P(	ext{No Ace}) = 1 - \frac{11}{20} = \frac{9}{20}$.

$A$ pack of cards contains $4$ aces,$4$ kings,$4$ queens,and $4$ jacks. Two cards are drawn at random. The probability that at least one of these is an ace is:

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