A paramagnetic substance in the form of a cub | vedclass

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(D) The volume of the cube is $V = (1\, cm)^3 = (10^{-2}\, m)^3 = 10^{-6}\, m^3$.The intensity of magnetization $I$ is defined as the magnetic dipole

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$3.3 	imes 10^{-4}$

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(D) The volume of the cube is $V = (1\, cm)^3 = (10^{-2}\, m)^3 = 10^{-6}\, m^3$.The intensity of magnetization $I$ is defined as the magnetic dipole moment per unit volume:$I = \frac{M}{V} = \frac{20 	imes 10^{-6}\, J/T}{10^{-6}\, m^3} = 20\, A/m$.The magnetic susceptibility $\chi$ is given by the ratio of the intensity of magnetization $I$ to the magnetic intensity $H$:$\chi = \frac{I}{H}$.Given $H = 60 	imes 10^3\, A/m$,we have:$\chi = \frac{20}{60 	imes 10^3} = \frac{1}{3} 	imes 10^{-3} = 0.333 	imes 10^{-3} = 3.33 	imes 10^{-4}$.

$A$ paramagnetic substance in the form of a cube with sides $1\, cm$ has a magnetic dipole moment of $20 \times 10^{-6}\, J/T$ when a magnetic intensity of $60 \times 10^3\, A/m$ is applied. Its magnetic susceptibility is

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