A particle has an initial velocity of (3hat i | vedclass

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(D) Given: Initial velocity $\vec{u} = (3\hat{i} + 4\hat{j}) \; ms^{-1}$,acceleration $\vec{a} = (0.4\hat{i} + 0.3\hat{j}) \; ms^{-2}$,and time $t = 1

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$7\sqrt{2}$ unit

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(D) Given: Initial velocity $\vec{u} = (3\hat{i} + 4\hat{j}) \; ms^{-1}$,acceleration $\vec{a} = (0.4\hat{i} + 0.3\hat{j}) \; ms^{-2}$,and time $t = 10 \; s$.Using the first equation of motion for vectors: $\vec{v} = \vec{u} + \vec{a}t$.Substituting the values: $\vec{v} = (3\hat{i} + 4\hat{j}) + (0.4\hat{i} + 0.3\hat{j}) 	imes 10$.$\vec{v} = (3\hat{i} + 4\hat{j}) + (4\hat{i} + 3\hat{j}) = 7\hat{i} + 7\hat{j}$.The speed is the magnitude of the velocity vector $\vec{v}$.$|\vec{v}| = \sqrt{7^2 + 7^2} = \sqrt{49 + 49} = \sqrt{98} = 7\sqrt{2} \; ms^{-1}$.

$A$ particle has an initial velocity of $(3\hat i + 4\hat j) \; ms^{-1}$ and an acceleration of $(0.4\hat i + 0.3\hat j) \; ms^{-2}$. Its speed after $10 \; s$ is:

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