$A$ particle of mass $m$ carrying charge $q$ is accelerated by a potential difference $V$. It enters perpendicularly into a region of uniform magnetic field $B$ and executes a circular arc of radius $R$. Then,$\frac{q}{m}$ equals:

  • A
    $\frac{2 V}{B^2 R^2}$
  • B
    $\frac{V}{2 B R}$
  • C
    $\frac{V B}{2 R}$
  • D
    $\frac{m V}{B R}$

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