A particle of mass m moving horizontally with | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let the velocity of the particle and the wedge be $v_1$ and $v_2$ respectively when the particle reaches the maximum height $h$ relative to the we

Vedclass · Accepted Answer

$\frac{mv_0}{M+m}$

Vedclass · Answer

(B) Let the velocity of the particle and the wedge be $v_1$ and $v_2$ respectively when the particle reaches the maximum height $h$ relative to the wedge. At this point,both the particle and the wedge move with the same horizontal velocity $v_2$ because the particle is at the peak of its trajectory relative to the wedge.Applying the law of conservation of linear momentum in the horizontal direction:$mv_0 = (M + m)v_2$$v_2 = \frac{mv_0}{M + m}$Applying the law of conservation of mechanical energy:$\frac{1}{2}mv_0^2 = \frac{1}{2}(M + m)v_2^2 + mgh$Substituting the value of $v_2$ into the energy equation confirms that the horizontal velocity $v_2$ is determined solely by momentum conservation at the point where the particle is at height $h$ relative to the wedge.

$A$ particle of mass $m$ moving horizontally with velocity $v_0$ strikes a smooth wedge of mass $M$,as shown in the figure. After the collision,the particle starts moving up the inclined face of the wedge and rises to a height $h$. The final velocity of the wedge $v_2$ is

Similar Questions

$A$ raindrop of mass $1.00 \, g$ falling from a height of $1 \, km$ hits the ground with a speed of $50 \, m s^{-1}$. Calculate
$(a)$ the loss of $PE$ of the drop
$(b)$ the gain in $KE$ of the drop
$(c)$ Is the gain in $KE$ equal to loss of $PE$? If not,why?
Take $g = 10 \, m s^{-2}$.

$A$ constant force $\vec{F} = 3\hat{i} - 2\hat{j} - \hat{k} \text{ N}$ causes a displacement $\vec{r} = 2\hat{i} - 3\hat{j} - 3\hat{k} \text{ m}$ in $2 \text{ s}$. The work done and the power are respectively:

Which of the following statements is $NOT$ true?

$A$ block of mass '$m$' with an initial kinetic energy '$E$' moves up an inclined plane of inclination '$\theta$'. If '$\mu$' is the coefficient of friction between the plane and the body, the work done against friction before coming to rest is

Vedclass Test Series

Exam Paper Generator

Online Exam Module