A particle undergoes uniform circular motion. | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The angular momentum $\vec{L}$ of a particle about a point is given by $\vec{L} = \vec{r} 	imes \vec{p}$.For a particle in uniform circular motio

Vedclass · Accepted Answer

Centre of the circle

Vedclass · Answer

(A) The angular momentum $\vec{L}$ of a particle about a point is given by $\vec{L} = \vec{r} 	imes \vec{p}$.For a particle in uniform circular motion,the force acting on it is the centripetal force,which is always directed towards the centre of the circle.The torque $\vec{	au}$ about the centre of the circle is given by $\vec{	au} = \vec{r} 	imes \vec{F}$.Since the force $\vec{F}$ is directed towards the centre,the position vector $\vec{r}$ and the force vector $\vec{F}$ are collinear (angle between them is $180^{\circ}$ or $0^{\circ}$).Therefore,the torque $\vec{	au} = 0$ about the centre.Since the external torque about the centre is zero,the angular momentum of the particle about the centre remains conserved.

$A$ particle undergoes uniform circular motion. About which point in the plane of the circle will the angular momentum of the particle remain conserved?

Similar Questions

Chemical $A$ is used for water softening to remove temporary hardness. $A$ reacts with sodium carbonate to generate caustic soda. When $CO_2$ is bubbled through a solution of $A$,it turns cloudy. What is the chemical formula of $A$?

The height of water in a tank is $H$. The range of the liquid emerging out from a hole in the wall of the tank at a depth $\frac{3H}{4}$ from the upper surface of water will be

The solution of the differential equation $(3xy + y^2)dx + (x^2 + xy)dy = 0$ is

To convert a galvanometer into a voltmeter,one should connect a

If the lines $2x + 3y + 12 = 0$ and $x - y + k = 0$ are conjugate with respect to the parabola $y^2 = 8x$,then $k$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module