A passenger buys 5 tickets for Ahmadabad to N | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let the cost of a ticket from Ahmadabad to Nadiad be Rs. $x$ and the cost of a ticket from Ahmadabad to Vadodara be Rs. $y$.According to the probl

Vedclass · Accepted Answer

Cost of ticket for Ahmadabad to Nadiad is Rs. $50$ and for Ahmadabad to Vadodara is Rs. $80$.

Vedclass · Answer

(A) Let the cost of a ticket from Ahmadabad to Nadiad be Rs. $x$ and the cost of a ticket from Ahmadabad to Vadodara be Rs. $y$.According to the problem,we have two equations:$1) 5x + 10y = 1050$Dividing by $5$,we get: $x + 2y = 210$$2) x + y = 130$Subtracting equation $(2)$ from equation $(1)$:$(x + 2y) - (x + y) = 210 - 130$$y = 80$Substituting $y = 80$ into equation $(2)$:$x + 80 = 130$$x = 130 - 80 = 50$Therefore,the cost of a ticket from Ahmadabad to Nadiad is Rs. $50$ and the cost of a ticket from Ahmadabad to Vadodara is Rs. $80$.

Similar Questions

If $(1, y)$ is the solution of the linear equation of two variables $2x + 3y = 8$,then $y = \ldots$

Solve the following pairs of equations:
$\frac{2xy}{x+y} = \frac{3}{2}$
$\frac{xy}{2x-y} = \frac{-3}{10}, \quad x+y \neq 0, 2x-y \neq 0$

The pair of equations $5x - y = 9$ and $10x - 18 = 2y$ is $\ldots \ldots \ldots \ldots$

Two years ago,Salim was thrice as old as his daughter and six years later,he will be four years older than twice her age. How old are they now? (in $year$)

For the pair of equations $\frac{2}{x} + \frac{3}{y} = 3$ and $\frac{3}{x} + \frac{2}{y} = 7$,find the value of $\frac{3}{x} + \frac{3}{y}$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module