A person travels 10, km north and 20, km east | vedclass

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Question

(A) Let the initial point be $A$,the point after traveling north be $B$,and the final point after traveling east be $C$.The displacement is the straig

Vedclass · Accepted Answer

$22.36$

Vedclass · Answer

(A) Let the initial point be $A$,the point after traveling north be $B$,and the final point after traveling east be $C$.The displacement is the straight-line distance from the initial point $A$ to the final point $C$,which is the hypotenuse of the right-angled triangle $ABC$.Using the Pythagorean theorem:$AC = \sqrt{AB^2 + BC^2}$Given $AB = 10\, km$ and $BC = 20\, km$.$AC = \sqrt{10^2 + 20^2} = \sqrt{100 + 400} = \sqrt{500}$$AC = 10\sqrt{5} \approx 22.36\, km$.

$A$ person travels $10\, km$ north and $20\, km$ east. What will be the displacement from the initial point in $km$?

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