A playground is in the shape of a rectangle. | vedclass

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(A) The rate is $25$ $paisa$ per $m^2$,which is equal to $₹ \frac{25}{100} = ₹ \frac{1}{4}$ per $m^2$.Area of the rectangular field = $\frac{	ext{Tot

Vedclass · Accepted Answer

$1250$

Vedclass · Answer

(A) The rate is $25$ $paisa$ per $m^2$,which is equal to $₹ \frac{25}{100} = ₹ \frac{1}{4}$ per $m^2$.Area of the rectangular field = $\frac{	ext{Total Expenditure}}{	ext{Rate per } m^2} = \frac{1000}{1/4} = 4000\, m^2$.Since the area of a rectangle is $	ext{length} 	imes 	ext{breadth}$,we have $4000 = 	ext{length} 	imes 50$.Therefore,the original length = $\frac{4000}{50} = 80\, m$.If the length is increased by $20\, m$,the new length = $80 + 20 = 100\, m$.The new area = $100\, m 	imes 50\, m = 5000\, m^2$.The new expenditure = $	ext{New Area} 	imes 	ext{Rate} = 5000 	imes \frac{1}{4} = ₹ 1250$.

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