Four circular cardboard pieces,each of radius | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) When four circles of radius $r = 7\, cm$ are placed such that each touches two others,their centers form a square with side length $s = 2r = 14\,

Vedclass · Accepted Answer

$42$

Vedclass · Answer

(B) When four circles of radius $r = 7\, cm$ are placed such that each touches two others,their centers form a square with side length $s = 2r = 14\, cm$.The area of this square is $s^2 = 14 	imes 14 = 196\, cm^2$.The space enclosed by the four pieces is the area of the square minus the area of the four quadrants of the circles lying inside the square.Each quadrant has an angle of $90^\circ$. The total area of the four quadrants is $4 	imes (\frac{90}{360} 	imes \pi r^2) = \pi r^2 = \frac{22}{7} 	imes 7 	imes 7 = 154\, cm^2$.Therefore,the required enclosed area is $196 - 154 = 42\, cm^2$.

Four circular cardboard pieces,each of radius $7\, cm$,are placed in such a way that each piece touches two other pieces. The area of the space enclosed by the four pieces is.......$cm^2$.

Similar Questions

$A$ circle and a rectangle have the same perimeter. The sides of the rectangle are $18 \text{ cm}$ and $26 \text{ cm}$. The area of the circle is .......... $\text{cm}^2$. [Take $\pi = \frac{22}{7}$]

Perimeter of a square and an equilateral triangle is equal. If the diagonal of the square is $12 \sqrt{2} \text{ cm}$,then find the area of the equilateral triangle.

The two adjacent sides of a parallelogram are $60 \, m$ and $40 \, m$ and one of the diagonals is $80 \, m$ long. The area of the parallelogram is

The length of each side of an equilateral triangle is $12\, cm$. The height of the triangle is

An equilateral triangle is cut up into smaller equilateral triangles with side $1/6$ of the original. Find the number of triangles thus formed?

Vedclass Test Series

Exam Paper Generator

Online Exam Module