$A$ point source of $100\,W$ emits light with $5\%$ efficiency. At a distance of $5\,m$ from the source,the intensity produced by the electric field component is:

In a plane electromagnetic wave,the magnetic field is given by $\vec{B} = 3 \times 10^{-7} \sin (100 \pi x + 10^{12} t) \ T$. The wavelength of the wave is (where $x$ is in meters and $t$ is in seconds). (in $m$)

The magnitude of the electric field of a plane electromagnetic wave travelling in free space is $E$. If $\mu_0$ and $\varepsilon_0$ are respectively permeability and permittivity of the free space,then the magnitude of magnetic field of the wave is

The electric field strength in an $EM$ wave is $10^4 \, V/m$. The magnitude of the magnetic field strength (in tesla) will be:

The intensity of the light from a bulb incident on a surface is $0.22 \, W/m^2$. The amplitude of the magnetic field in this light wave is . . . . . . $\times 10^{-9} \, T$. (Given: Permittivity of vacuum $\epsilon_0 = 8.85 \times 10^{-12} \, C^2 N^{-1} m^{-2}$,speed of light in vacuum $c = 3 \times 10^8 \, m/s$)

$A$ plane electromagnetic wave propagating along the y-direction can have the following pair of electric field $(\vec{E})$ and magnetic field $(\vec{B})$ components.