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Question

(B) The intensity $I$ of an electromagnetic wave is related to the electric field amplitude $E_0$ by the formula: $I = \frac{1}{2} \epsilon_0 E_0^2 c$

Vedclass · Accepted Answer

$43$

Vedclass · Answer

(B) The intensity $I$ of an electromagnetic wave is related to the electric field amplitude $E_0$ by the formula: $I = \frac{1}{2} \epsilon_0 E_0^2 c$.Rearranging for $E_0$: $E_0 = \sqrt{\frac{2I}{\epsilon_0 c}}$.Substituting the given values: $E_0 = \sqrt{\frac{2 	imes 0.22}{8.85 	imes 10^{-12} 	imes 3 	imes 10^8}} = \sqrt{\frac{0.44}{26.55 	imes 10^{-4}}} = \sqrt{165.72} \approx 12.873 \, V/m$.The amplitude of the magnetic field $B_0$ is given by $B_0 = \frac{E_0}{c}$.$B_0 = \frac{12.873}{3 	imes 10^8} = 4.291 	imes 10^{-8} \, T$.Expressing this in terms of $10^{-9} \, T$: $B_0 = 42.91 	imes 10^{-9} \, T \approx 43 	imes 10^{-9} \, T$.

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