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(B) In a series combination,the charge $Q$ on each capacitor is the same.First,calculate the equivalent capacitance $C_{eq}$ of the series combination

Vedclass · Accepted Answer

$4.8 	imes 10^{-4}\, C$

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(B) In a series combination,the charge $Q$ on each capacitor is the same.First,calculate the equivalent capacitance $C_{eq}$ of the series combination:$C_{eq} = \frac{C_1 C_2}{C_1 + C_2} = \frac{2.0 	imes 8.0}{2.0 + 8.0}\, \mu F = \frac{16}{10}\, \mu F = 1.6\, \mu F$.The charge $Q$ on the capacitors is given by $Q = C_{eq} V$.Substituting the values: $Q = 1.6 	imes 10^{-6}\, F 	imes 300\, V = 480 	imes 10^{-6}\, C = 4.8 	imes 10^{-4}\, C$.Thus,the charge on the $2.0\,\mu F$ capacitor is $4.8 	imes 10^{-4}\, C$.

$A$ potential difference of $300\, V$ is applied to a combination of $2.0\,\mu F$ and $8.0\,\mu F$ capacitors connected in series. The charge on the $2.0\,\mu F$ capacitor is

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