Three capacitors $2\,\mu F$,$3\,\mu F$,and $6\,\mu F$ are joined in series with each other. What is the minimum effective capacitance in $\mu F$?

Two capacitors $C_1$ and $C_2$ in a circuit are joined as shown in the figure. The potential of point $A$ is $V_1$ and that of point $B$ is $V_2$. The potential at point $D$ will be

Four capacitors are connected as shown in the figure. If $C_1, C_2, C_3$ and $C_4$ are in the ratio of $1: 2: 3: 4$,then the ratio of the charges on the capacitors $C_2$ and $C_4$ is

$A$ series combination of three capacitors of capacities $1\,\mu F$,$2\,\mu F$,and $8\,\mu F$ is connected to a battery of $e.m.f.$ $13\,V$. The potential difference across the plates of the $2\,\mu F$ capacitor will be.....$V$

In the circuit shown in the figure,the effective capacitance between $A$ and $B$ is ...... $\mu F$.

Four capacitors of equal capacitance have an equivalent capacitance $C_1$ when connected in series and an equivalent capacitance $C_2$ when connected in parallel. The ratio $\frac{C_1}{C_2}$ is: