Class 12PhysicsElectrostatic Potential and CapacitanceEquivalent Capacitance of Capacitor connected in Series and Parallel
EasyTwo capacitors $C_1$ and $C_2$ in a circuit are joined as shown in the figure. The potential of point $A$ is $V_1$ and that of point $B$ is $V_2$. The potential at point $D$ will be
- A$\frac{1}{2}(V_1+V_2)$
- B$\frac{C_2 V_1+C_1 V_2}{C_1+C_2}$
- C$\frac{C_1 V_1+C_2 V_2}{C_1+C_2}$
- D$\frac{C_2 V_2-C_1 V_2}{C_1+C_2}$
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