$A$ pressure-pump has a horizontal tube of cross-sectional area $10 \, cm^{2}$ for the outflow of water at a speed of $20 \, m/s$. The force exerted on the vertical wall just in front of the tube,which stops the water horizontally flowing out of the tube,is $... N$ [Given: density of water $= 1000 \, kg/m^{3}$].

$A$ gardener waters the plants using a pipe of diameter $1\,mm$. The water comes out at a rate of $10\,cm^3/s$. The reactionary force exerted on the hand of the gardener is:

$A$ uniformly tapering vessel is filled with a liquid of density $900 \, kg/m^3$. The force that acts on the base of the vessel due to the liquid is ......... $N$. $(g = 10 \, m/s^2)$

$A$ jet of liquid of cross-sectional area $a$ strikes a wall making an angle $\theta$ with the wall. The liquid strikes the wall with velocity $v$ and rebounds elastically. If the density of the liquid is $\rho$,the normal force on the wall is:

$A$ tube of length $50\,cm$ is filled completely with an incompressible liquid of mass $250\,g$ and closed at both ends. The tube is then rotated in a horizontal plane about one of its ends with a uniform angular velocity $\omega = x \sqrt{F} \text{ rad } s^{-1}$. If $F$ is the force exerted by the liquid at the other end,then the value of $x$ will be:

Mercury is filled in a tube of radius $2 \,cm$ up to a height of $30 \,cm$. The force exerted by mercury on the bottom of the tube is . . . . . . $N$.
(Given: atmospheric pressure $P_0 = 10^5 \,N/m^2$,density of mercury $\rho = 1.36 \times 10^4 \,kg/m^3$,$g = 10 \,m/s^2$,$\pi = \frac{22}{7}$)