A prism having an apex angle 4^o and refracti | vedclass

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(C) The deviation produced by the prism is given by $\delta_{prism} = (\mu - 1)A = (1.5 - 1) 	imes 4^o = 2^o$.The ray enters the prism normally,so it

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$178$

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(C) The deviation produced by the prism is given by $\delta_{prism} = (\mu - 1)A = (1.5 - 1) 	imes 4^o = 2^o$.The ray enters the prism normally,so it passes undeviated through the first surface and deviates by $2^o$ at the second surface.This deviated ray strikes the mirror at an angle of incidence $i = 2^o$ (since the deviation is the angle between the incident and emergent ray).The deviation produced by the mirror is $\delta_{mirror} = 180^o - 2i = 180^o - 2(2^o) = 176^o$.The total deviation is $\delta_{total} = \delta_{prism} + \delta_{mirror} = 2^o + 176^o = 178^o$.

$A$ prism having an apex angle $4^o$ and refractive index $1.5$ is located in front of a vertical plane mirror as shown in the figure. Through what total angle is the ray deviated after reflection from the mirror (in $^o$)?

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