A projectile is thrown with speed 40 , m/s at | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The vertical displacement of a projectile is given by $y = (u \sin 	heta)t - \frac{1}{2}gt^2$.Since the projectile is at the same height at $t_1

Vedclass · Accepted Answer

$	an^{-1}\left(\frac{1}{\sqrt{3}}ight)$

Vedclass · Answer

(B) The vertical displacement of a projectile is given by $y = (u \sin 	heta)t - \frac{1}{2}gt^2$.Since the projectile is at the same height at $t_1 = 1 \, s$ and $t_2 = 3 \, s$,the sum of these times is equal to the time taken to reach the maximum height multiplied by $2$,which is the total time of flight for that specific height level.Specifically,$t_1 + t_2 = \frac{2u \sin 	heta}{g}$.Given $u = 40 \, m/s$,$g = 10 \, m/s^2$,$t_1 = 1 \, s$,and $t_2 = 3 \, s$:$1 + 3 = \frac{2 	imes 40 	imes \sin 	heta}{10}$.$4 = 8 \sin 	heta$.$\sin 	heta = \frac{4}{8} = \frac{1}{2}$.Therefore,$	heta = 30^{\circ}$.The angle of projection is $	heta = 	an^{-1}(	an 30^{\circ}) = 	an^{-1}\left(\frac{1}{\sqrt{3}}ight)$.

$A$ projectile is thrown with speed $40 \, m/s$ at an angle $\theta$ from the horizontal. It is found that the projectile is at the same height at $1 \, s$ and $3 \, s$. What is the angle of projection?

Similar Questions

$A$ projectile is thrown with a velocity of $50 \, ms^{-1}$ at an angle of $53^o$ with the horizontal. The equation of the trajectory is given by:

On which factors does the value of the range of a projectile depend? On which factors does the maximum value of the range depend?

$A$ stone is projected at an angle of $30^{\circ}$ to the horizontal. The ratio of the kinetic energy of the stone at the point of projection to its kinetic energy at the highest point of its flight will be:

$A$ projectile covers double the range compared to its maximum height attained. The angle of projection is

For a projectile, if $\alpha$ is the angle of projection, $R$ is the range, $h$ is the maximum height, and $T$ is the time of flight, then:

Vedclass Test Series

Exam Paper Generator

Online Exam Module