$A$ ray of light is incident on a transparent glass slab of refractive index $1.62$. The reflected and the refracted rays are mutually perpendicular. The angle of incidence is.......$^o$

For a given medium,the polarizing angle is $60^{\circ}$. The critical angle for this medium is . . . . . .

The critical angle of a certain medium is $\sin^{-1}\left(\frac{3}{5}\right)$. The polarizing angle of the medium is

$A$ ray of light is incident on the surface of a glass plate at an angle of incidence equal to Brewster's angle $\Phi$. If $\mu$ denotes the refractive index of glass with respect to air, then what will be the angle between the reflected and refracted rays?

$A$ ray of light is incident at the polarising angle $\theta$ on an air-glass interface. If $\lambda_a$ and $\lambda_g$ are the wavelengths of light in air and glass respectively, then:

At what angle of incidence $i$ will the light reflected from water be completely plane-polarized (in $^\circ$)? (Given refractive index of water $\mu = 1.33$)