A right triangle ABC with sides 5 , cm, 12 , | vedclass

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Question

(B) The sides of the right triangle are $5 \, cm, 12 \, cm$,and $13 \, cm$.Since the right-angled triangle is revolved about the $12 \, cm$ side,the h

Vedclass · Accepted Answer

$100 \pi \, cm^3$

Vedclass · Answer

(B) The sides of the right triangle are $5 \, cm, 12 \, cm$,and $13 \, cm$.Since the right-angled triangle is revolved about the $12 \, cm$ side,the height of the resulting cone is $h = 12 \, cm$ and the radius of the base is $r = 5 \, cm$.The volume of a cone is given by the formula $V = \frac{1}{3} \pi r^2 h$.Substituting the values,we get:$V = \frac{1}{3} 	imes \pi 	imes (5)^2 	imes 12 \, cm^3$$V = \frac{1}{3} 	imes \pi 	imes 25 	imes 12 \, cm^3$$V = \pi 	imes 25 	imes 4 \, cm^3$$V = 100 \pi \, cm^3$.Thus,the volume of the solid obtained is $100 \pi \, cm^3$.

$A$ right triangle $ABC$ with sides $5 \, cm, 12 \, cm$ and $13 \, cm$ is revolved about the side $12 \, cm$. Find the volume of the solid so obtained.

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