A rubber ball is taken to a 100, m deep lake | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The change in pressure $\Delta P$ at a depth $h$ is given by $\Delta P = h \rho g$.Given: $h = 100\, m$,$\rho = 10^3\, kg/m^3$ (density of water),

Vedclass · Accepted Answer

$1	imes10^{9} \,N/m^2$

Vedclass · Answer

(D) The change in pressure $\Delta P$ at a depth $h$ is given by $\Delta P = h ho g$.Given: $h = 100\, m$,$ho = 10^3\, kg/m^3$ (density of water),$g = 10\, m/s^2$,and fractional volume change $\frac{-\Delta V}{V} = 0.1\% = 0.001 = 10^{-3}$.The bulk modulus $\beta$ is defined as $\beta = \frac{\Delta P}{(-\Delta V/V)}$.Substituting the values: $\beta = \frac{100 	imes 10^3 	imes 10}{10^{-3}} = \frac{10^6}{10^{-3}} = 10^9\, N/m^2$.

$A$ rubber ball is taken to a $100\, m$ deep lake and its volume changes by $0.1\%$. The bulk modulus of rubber is nearly

Similar Questions

The wrong statement in the following is

Explain hydraulic stress,volume stress and volume strain.

Bulk modulus was first defined by

When a pressure of $100 \, atm$ is applied to a rubber ball,its volume decreases by $0.01 \%$. What is the bulk modulus of the rubber?

Vedclass Test Series

Exam Paper Generator

Online Exam Module