A sample of an ideal gas undergoes an isother | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For an isothermal process,the temperature $T$ remains constant $(dT = 0)$.Since the internal energy $U$ of an ideal gas depends only on temperatur

Vedclass · Accepted Answer

$dQ = +ve, dU = 0, dW = +ve$

Vedclass · Answer

(B) For an isothermal process,the temperature $T$ remains constant $(dT = 0)$.Since the internal energy $U$ of an ideal gas depends only on temperature $(U = f(T))$,the change in internal energy $dU = 0$.During expansion,the gas does work on the surroundings,so the work done by the gas is positive $(dW > 0)$.According to the first law of thermodynamics,$dQ = dU + dW$.Substituting the values,$dQ = 0 + dW$,which implies $dQ = dW$.Since $dW > 0$,it follows that $dQ > 0$ (heat is supplied to the system).Therefore,$dQ = +ve$,$dU = 0$,and $dW = +ve$.

$A$ sample of an ideal gas undergoes an isothermal expansion. If $dQ$,$dU$,and $dW$ represent the amount of heat supplied,the change in internal energy,and the work done respectively,then:

Similar Questions

$A$ gas is compressed at constant temperature. Its molecules gain:

Which of the following is a slow process?

What is the value of the specific heat of a gas during an isothermal process?

In an isothermal change, an ideal gas obeys:

Vedclass Test Series

Exam Paper Generator

Online Exam Module