A sample of gas occupies 100 mL at 27 ^oC a | vedclass

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(C) According to the combined gas law,$\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}$.Given: $P_1 = 740 \ mm$,$V_1 = 100 \ mL$,$T_1 = 27 + 273 = 300 \ K$.

Vedclass · Accepted Answer

$-33$

Vedclass · Answer

(C) According to the combined gas law,$\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}$.Given: $P_1 = 740 \ mm$,$V_1 = 100 \ mL$,$T_1 = 27 + 273 = 300 \ K$.Given: $P_2 = 740 \ mm$,$V_2 = 80 \ mL$.Since pressure is constant $(P_1 = P_2)$,the equation simplifies to Charles's Law: $\frac{V_1}{T_1} = \frac{V_2}{T_2}$.$T_2 = \frac{V_2 	imes T_1}{V_1} = \frac{80 \ mL 	imes 300 \ K}{100 \ mL} = 240 \ K$.Converting to Celsius: $T_2 = 240 - 273 = -33 \ ^oC$.

$A$ sample of gas occupies $100 \ mL$ at $27 \ ^oC$ and $740 \ mm$ pressure. When its volume is changed to $80 \ mL$ at $740 \ mm$ pressure,the temperature of the gas will be ............. $^oC$

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