$A$ satellite $A$ of mass $m$ is at a distance of $r$ from the centre of the earth. Another satellite $B$ of mass $2m$ is at a distance of $2r$ from the earth's centre. Their time periods are in the ratio of:

The ratio of the distances of two planets from the sun is $1.38$. The ratio of their period of revolution around the sun is

$A$ geostationary satellite is taken from one orbit to another orbit,whose distance from the centre of the Earth is $2$ times that of the earlier orbit. The time period in the second orbit is how many hours?

The time period of a satellite of the Earth is $5 \text{ hours}$. If the separation between the Earth and the satellite is increased to four times the previous value, the new time period of the satellite will be: (in $\text{ hours}$)

$A$ body revolves around the sun $27$ times faster than the earth. What is the ratio of their orbital radii?

Let the speed of the planet at the perihelion $P$ in the figure be $v_{P}$ and the Sun-planet distance $SP$ be $r_{P}$. Relate $\{r_{P}, v_{P}\}$ to the corresponding quantities at the aphelion $\{r_{A}, v_{A}\}$. Will the planet take equal times to traverse $BAC$ and $CPB$?