$A$ semicircular sheet of metal of diameter $28 \, cm$ is bent into an open conical cup. The capacity of the cup (taking $\pi = \frac{22}{7}$) is (in $cm^3$):

  • A
    $624.26$
  • B
    $622.36$
  • C
    $622.56$
  • D
    $623.20$

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