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(B) To maximize the average rate at which energy is supplied,the power in the circuit must be maximum.In a series $LCR$ circuit,the power is maximum a

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$40$

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(B) To maximize the average rate at which energy is supplied,the power in the circuit must be maximum.In a series $LCR$ circuit,the power is maximum at the condition of resonance.At resonance,the inductive reactance equals the capacitive reactance,i.e.,$X_L = X_C$.Given $X_L = 79.6\,\Omega$ and frequency $f = 50\,Hz$.The formula for capacitive reactance is $X_C = \frac{1}{2\pi f C}$.Equating $X_L$ and $X_C$: $79.6 = \frac{1}{2 	imes 3.1416 	imes 50 	imes C}$.$C = \frac{1}{314.16 	imes 79.6} \approx \frac{1}{25007} \approx 3.998 	imes 10^{-5}\,F$.$C \approx 40 	imes 10^{-6}\,F = 40\,\mu F$.

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