A ship of mass 3 times 10^7 , kg initially at | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given: Mass $m = 3 	imes 10^7 \, kg$,Force $F = 5 	imes 10^4 \, N$,Distance $s = 3 \, m$,Initial velocity $u = 0$.According to Newton's second l

Vedclass · Accepted Answer

$0.1$

Vedclass · Answer

(C) Given: Mass $m = 3 	imes 10^7 \, kg$,Force $F = 5 	imes 10^4 \, N$,Distance $s = 3 \, m$,Initial velocity $u = 0$.According to Newton's second law,acceleration $a = \frac{F}{m} = \frac{5 	imes 10^4}{3 	imes 10^7} = \frac{5}{3} 	imes 10^{-3} \, m/s^2$.Using the kinematic equation $v^2 - u^2 = 2as$:$v^2 = 0^2 + 2 	imes \left( \frac{5 	imes 10^4}{3 	imes 10^7} ight) 	imes 3$.$v^2 = 2 	imes \left( \frac{5}{3} 	imes 10^{-3} ight) 	imes 3 = 10 	imes 10^{-3} = 10^{-2}$.$v = \sqrt{10^{-2}} = 0.1 \, m/s$.

$A$ ship of mass $3 \times 10^7 \, kg$ initially at rest is pulled by a force of $5 \times 10^4 \, N$ through a distance of $3 \, m$. Assuming that the resistance due to water is negligible,the speed of the ship is ........... $m/s$.

Similar Questions

If force and displacement of a particle in the direction of force are doubled,the work done would be:

Show that a force that does no work must be a velocity-dependent force.

How much work does a pulling force of $40 \,N$ do on a $20 \,kg$ box in pulling it $8 \,m$ across the floor at a constant speed? The pulling force is directed at $60^\circ$ above the horizontal.

$A$ force $F = (5\hat{i} + 3\hat{j}) \ N$ acts on an object,causing a displacement of $r = (2\hat{i} - 1\hat{j}) \ m$. Calculate the work done in $J$.

$A$ heavy object and a light object are placed on the same surface. If the same force is applied to both for the same displacement,on which object is more work done by the force?

Vedclass Test Series

Exam Paper Generator

Online Exam Module