A shot-put is a metallic sphere of radius 4.9 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The shot-put is a solid sphere. The mass of the sphere is calculated by multiplying its volume by its density.Step $1$: Calculate the volume of th

Vedclass · Accepted Answer

$3.85$

Vedclass · Answer

(B) The shot-put is a solid sphere. The mass of the sphere is calculated by multiplying its volume by its density.Step $1$: Calculate the volume of the sphere.The formula for the volume of a sphere is $V = \frac{4}{3} \pi r^3$.Given $r = 4.9 \, cm$,we have:$V = \frac{4}{3} 	imes \frac{22}{7} 	imes (4.9)^3$$V = \frac{4}{3} 	imes \frac{22}{7} 	imes 4.9 	imes 4.9 	imes 4.9$$V = \frac{4}{3} 	imes 22 	imes 0.7 	imes 4.9 	imes 4.9$$V \approx 493.0 \, cm^3$.Step $2$: Calculate the mass of the shot-put.Mass = Volume $	imes$ DensityMass = $493.0 \, cm^3 	imes 7.8 \, g/cm^3$Mass = $3845.4 \, g$.Step $3$: Convert the mass into kilograms.Since $1 \, kg = 1000 \, g$,Mass = $\frac{3845.4}{1000} \, kg \approx 3.85 \, kg$.

$A$ shot-put is a metallic sphere of radius $4.9 \, cm$. If the density of the metal is $7.8 \, g/cm^3$,find the mass of the shot-put. (in $, kg$)

Similar Questions

$A$ metallic ball of radius $9 \,cm$ is melted and recast into three metallic balls. If the radii of two balls are $1 \,cm$ and $6 \,cm$,find the radius of the third ball (in $cm$).

The diameters of two spheres are in the ratio $3: 5$. What is the ratio of their volumes?

The radii of three metal spheres are $3 \,cm, 4 \,cm$ and $5 \,cm$ respectively. They are melted into a single solid sphere. Find the radius of the new solid sphere (in $cm$).

$A$ hemispherical bowl has a radius of $3.5\, cm$. What would be the volume of water it would contain (in $, cm^{3}$)?

Find the volume of a sphere with radius $2.1 \, m$ (in $m^{3}$).

Vedclass Test Series

Exam Paper Generator

Online Exam Module