A slit of width a is illuminated by red light | vedclass

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(C) For single slit diffraction,the condition for the $n^{th}$ minimum is given by $a \sin 	heta = n \lambda$.Given: $n = 1$,$\lambda = 6500 \,\, \ma

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$1.3 \,\, \mu	ext{m}$

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(C) For single slit diffraction,the condition for the $n^{th}$ minimum is given by $a \sin 	heta = n \lambda$.Given: $n = 1$,$\lambda = 6500 \,\, \mathring{A} = 6500 	imes 10^{-10} \,\, 	ext{m}$,and $	heta = 30^{\circ}$.Substituting these values into the formula:$a \sin 30^{\circ} = 1 	imes 6500 	imes 10^{-10} \,\, 	ext{m}$Since $\sin 30^{\circ} = 0.5$,we have:$a 	imes 0.5 = 6500 	imes 10^{-10} \,\, 	ext{m}$$a = 13000 	imes 10^{-10} \,\, 	ext{m} = 1.3 	imes 10^{-6} \,\, 	ext{m} = 1.3 \,\, \mu	ext{m}$.

$A$ slit of width $a$ is illuminated by red light of wavelength $6500 \,\, \mathring{A}$. The first minimum will fall at $\theta = 30^{\circ}$ if $a$ is equal to:

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