$A$ small block slides down from rest at point $A$ on the surface of a smooth cylinder,as shown. At point $B$,the block falls off (leaves) the cylinder. The equation relating the angles $\theta_1$ and $\theta_2$ is given by

  • A
    $\sin\ \theta_2 = \frac{2}{3}\sin\ \theta_1$
  • B
    $\sin\ \theta_2 = \frac{3}{2}\sin\ \theta_1$
  • C
    $\cos\ \theta_2 = \frac{2}{3}\cos\ \theta_1$
  • D
    $\cos\ \theta_2 = \frac{3}{2}\cos\ \theta_1$

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