A small electric dipole vec{p}_0,having a mom | vedclass

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Question

(D) The electric field inside a spherical shell is zero,so the dipole will not experience any torque and thus will not oscillate if $r

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$B, D$

Vedclass · Answer

(D) The electric field inside a spherical shell is zero,so the dipole will not experience any torque and thus will not oscillate if $r  R$,the electric field at the position of the dipole is $E = \frac{Q}{4 \pi \varepsilon_0 r^2}$,where $Q = 4 \pi R^2 \sigma$. Thus,$E = \frac{\sigma R^2}{\varepsilon_0 r^2}$.The torque on the dipole is $	au = -p_0 E \sin 	heta$. For small $	heta$,$\sin 	heta \approx 	heta$,so $	au = -p_0 E 	heta$.Using the equation of motion $	au = I \alpha$,we get $I \frac{d^2 	heta}{dt^2} = -p_0 E 	heta$,which represents simple harmonic motion with angular frequency $\omega = \sqrt{\frac{p_0 E}{I}}$.Substituting $E = \frac{\sigma R^2}{\varepsilon_0 r^2}$,we get $\omega = \sqrt{\frac{p_0 \sigma R^2}{\varepsilon_0 I r^2}} = \frac{R}{r} \sqrt{\frac{p_0 \sigma}{\varepsilon_0 I}}$.For $r = 2R$,$\omega = \frac{R}{2R} \sqrt{\frac{p_0 \sigma}{\varepsilon_0 I}} = \frac{1}{2} \sqrt{\frac{p_0 \sigma}{\varepsilon_0 I}} = \sqrt{\frac{p_0 \sigma}{4 \varepsilon_0 I}}$. Thus,statement $(C)$ is correct.For $r = 10R$,$\omega = \frac{R}{10R} \sqrt{\frac{p_0 \sigma}{\varepsilon_0 I}} = \frac{1}{10} \sqrt{\frac{p_0 \sigma}{\varepsilon_0 I}} = \sqrt{\frac{p_0 \sigma}{100 \varepsilon_0 I}}$. Thus,statement $(D)$ is correct.Therefore,statements $(B)$,$(C)$,and $(D)$ are correct. However,based on the provided options,the best choice is $(D)$.

Similar Questions

The electric field at point $p$ due to an electric dipole is $E$. The electric field at point $R$ on the equatorial line will be $\frac{E}{x}$. The value of $x$ is:

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