The electric field at point $p$ due to an electric dipole is $E$. The electric field at point $R$ on the equatorial line will be $\frac{E}{x}$. The value of $x$ is:

  • A
    $14$
  • B
    $15$
  • C
    $16$
  • D
    $17$

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Similar Questions

Two charges $+q$ and $-q$ are placed at a distance $a$ in a uniform electric field. The dipole moment of the combination is $2qa(\cos \theta \hat{i} + \sin \theta \hat{j})$, where $\theta$ is the angle between the direction of the field and the line joining the two charges. Which of the following statement$(s)$ is/are correct?

An electric dipole of length $20 \ cm$ having $\pm 3 \times 10^{-3} \ C$ charge is placed at $60^{\circ}$ with respect to a uniform electric field and experiences a torque of magnitude $6 \ N-m$. The potential energy of the dipole is:

If the electric field at a distance $x$ on the axis of an electric dipole is equal to the electric field at a distance $y$ on its equatorial line,what is the ratio $x : y$?

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An electrical dipole coincides on the $z$-axis and its midpoint is at the origin of the coordinate system. The electric field at an axial point at a distance $z$ from the origin is $\vec{E}(z)$ and the electric field at an equatorial point at a distance $y$ from the origin is $\vec{E}(y)$. Here $z = y \gg a$,so $\left| \frac{\vec{E}(z)}{\vec{E}(y)} \right| = . . . . . . . .$.

An electric dipole of length $0.5 \text{ }\mu\text{m}$ is placed with its axis making an angle of $30^{\circ}$ with a uniform electric field of $10^4 \text{ V/m}$. If it experiences a torque of $5 \times 10^{-9} \text{ Nm}$, the magnitude of the charge on the dipole is (given $\sin 30^{\circ} = 0.5$). (in $\text{ }\mu\text{C}$)

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