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Question

(C) According to Stokes' law,when a small spherical object of radius $a$ moves through a viscous fluid with a velocity $v$,it experiences a viscous dr

Vedclass · Accepted Answer

$6\pi \eta av$

Vedclass · Answer

(C) According to Stokes' law,when a small spherical object of radius $a$ moves through a viscous fluid with a velocity $v$,it experiences a viscous drag force $F$ that opposes its motion.The magnitude of this force is given by the formula:$F = 6\pi \eta av$Where:$F$ is the viscous force (drag force),$\eta$ is the coefficient of viscosity of the liquid,$a$ is the radius of the sphere,$v$ is the velocity of the sphere.Thus,the correct expression for the opposing force is $6\pi \eta av$.

$A$ small metal sphere of radius $a$ is falling with a velocity $v$ through a vertical column of a viscous liquid. If the coefficient of viscosity of the liquid is $\eta$,then the sphere encounters an opposing force of

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