(A) Total amount of solute present in the mixture is given by,$300 \times \frac{25}{100} + 400 \times \frac{40}{100} = 75 + 160 = 235 \, g$Total amoun

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(A) Total amount of solute present in the mixture is given by,$300 \times \frac{25}{100} + 400 \times \frac{40}{100} = 75 + 160 = 235 \, g$Total amount of solution $= 300 + 400 = 700 \, g$Therefore,mass percentage $(w/w)$ of the solute in the resulting solution $= \frac{235}{700} \times 100 \% = 33.57 \%$

Class 12 Chemistry Solutions Method of expressing concentration of solution

Medium

$A$ solution is obtained by mixing $300 \, g$ of $25 \%$ solution and $400 \, g$ of $40 \%$ solution by mass. Calculate the mass percentage of the resulting solution. (in $\%$)

A
$33.57$
B
$35.57$
C
$30.57$
D
$38.57$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Chemistry Questions

Chapter

Solutions

Subtopic

Method of expressing concentration of solution

If the mole fraction of the solute in liquid naphthalene $(C_{10}H_{8})$ is $0.2$,then the molality of the solution will be ............ $m$.

Medium

View Solution

The volume of water added to $500 \ mL$ of $0.5 \ M \ NaOH$ solution so that its strength becomes $10 \ mg \ mL^{-1}$ will be .......... $mL$.

Medium

View Solution

If $98 \, mg$ of $H_2SO_4$ is present in $100 \, g$ of solution,what is the molarity of the solution? (Given: density of solution = $1.25 \, g/mL$)

Difficult

View Solution

If a substance $A$ dissolves in a solution of a mixture of $B$ and $C$ with their respective number of moles as $n_A, n_B$ and $n_C$,the mole fraction of $C$ in the solution is:

EasyJEE MAIN 2024

View Solution

If $5 \ g$ $NaOH$ is dissolved in $450 \ mL$ of solution,the molarity of the solution is: $(Na=23, O=16, H=1 \ g \ mol^{-1})$ (in $M$)

EasyGSEB 2021

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

$A$ solution is obtained by mixing $300 \, g$ of $25 \%$ solution and $400 \, g$ of $40 \%$ solution by mass. Calculate the mass percentage of the resulting solution. (in $\%$)

Similar Questions

If the mole fraction of the solute in liquid naphthalene $(C_{10}H_{8})$ is $0.2$,then the molality of the solution will be ............ $m$.

The volume of water added to $500 \ mL$ of $0.5 \ M \ NaOH$ solution so that its strength becomes $10 \ mg \ mL^{-1}$ will be .......... $mL$.

If $98 \, mg$ of $H_2SO_4$ is present in $100 \, g$ of solution,what is the molarity of the solution? (Given: density of solution = $1.25 \, g/mL$)

If a substance $A$ dissolves in a solution of a mixture of $B$ and $C$ with their respective number of moles as $n_A, n_B$ and $n_C$,the mole fraction of $C$ in the solution is:

If $5 \ g$ $NaOH$ is dissolved in $450 \ mL$ of solution,the molarity of the solution is: $(Na=23, O=16, H=1 \ g \ mol^{-1})$ (in $M$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module