A solution of colourless salt H on boiling wi | vedclass

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(B) The gas evolved is $NH_3$ (ammonia),which is non-flammable. $NH_4^+$ salts react with $NaOH$ to release $NH_3$ gas: $NH_4^+ + OH^- \longrightarrow

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$A, B$

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(B) The gas evolved is $NH_3$ (ammonia),which is non-flammable. $NH_4^+$ salts react with $NaOH$ to release $NH_3$ gas: $NH_4^+ + OH^- \longrightarrow NH_3 + H_2O$. When the $NH_4^+$ ions are consumed,the evolution of $NH_3$ stops. If the salt contains an oxidizing anion like $NO_3^-$ or $NO_2^-$,the addition of $Zn$ dust in an alkaline medium reduces the anion to $NH_3$ gas,causing the evolution to restart. $NH_4NO_3 + 4Zn + 7NaOH \longrightarrow 4Na_2ZnO_2 + 2NH_3 + 2H_2O$. $NH_4NO_2 + 3Zn + 5NaOH \longrightarrow 3Na_2ZnO_2 + 2NH_3 + H_2O$. $NH_4Cl$ and $(NH_4)_2SO_4$ do not contain oxidizing anions,so they will not produce further $NH_3$ upon adding $Zn$ dust. Thus,$H$ can be $NH_4NO_3$ or $NH_4NO_2$.

$A$ solution of colourless salt $H$ on boiling with excess $NaOH$ produces a non-flammable gas. The gas evolution ceases after sometime. Upon addition of $Zn$ dust to the same solution,the gas evolution restarts. The colourless salt$(s)$ $H$ is (are):

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