A source of frequency nu gives 5 beats/second | vedclass

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Question

(B) The beat frequency is the absolute difference between the two frequencies.Given,for frequency $
u$ and $200 \;Hz$,the beat frequency is $5 \;Hz$.

Vedclass · Accepted Answer

$205$

Vedclass · Answer

(B) The beat frequency is the absolute difference between the two frequencies.Given,for frequency $
u$ and $200 \;Hz$,the beat frequency is $5 \;Hz$.So,$
u = 200 \pm 5$,which means $
u = 195 \;Hz$ or $
u = 205 \;Hz$ ... $(i)$For the second harmonic $2
u$ and $420 \;Hz$,the beat frequency is $10 \;Hz$.So,$2
u = 420 \pm 10$,which means $2
u = 410 \;Hz$ or $2
u = 430 \;Hz$.Dividing by $2$,we get $
u = 205 \;Hz$ or $
u = 215 \;Hz$ ... $(ii)$Comparing equations $(i)$ and $(ii)$,the common value is $
u = 205 \;Hz$.

$A$ source of frequency $\nu$ gives $5$ beats/second when sounded with a source of frequency $200 \;Hz$. The second harmonic of frequency $2\nu$ of the source gives $10$ beats/second when sounded with a source of frequency $420 \;Hz$. The value of $\nu$ is .... $Hz$.

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