A source voltage of 8V drives the diode in th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let $i$ be the current in the diode and $V$ be the voltage drop across it. According to Kirchhoff's voltage law for the given circuit:$i 	imes 10

Vedclass · Accepted Answer

$0.01$

Vedclass · Answer

(A) Let $i$ be the current in the diode and $V$ be the voltage drop across it. According to Kirchhoff's voltage law for the given circuit:$i 	imes 100 + V = 8$Rearranging the equation to express $i$ in terms of $V$:$i = -\frac{1}{100}V + \frac{8}{100}$$i = -(0.01)V + 0.08$Comparing this with the equation of a straight line $y = mx + c$,where $y = i$ and $x = V$,the slope $m$ is given by $-\frac{1}{R}$.The magnitude of the slope of the load line is $|m| = \frac{1}{R} = \frac{1}{100} = 0.01 	ext{ } \Omega^{-1}$.

$A$ source voltage of $8V$ drives the diode in the figure through a current-limiting resistor of $100 \Omega$. Then the magnitude of the slope of the load line on the $V-I$ characteristics of the diode is

Similar Questions

In the circuit,if the forward voltage drop for the diode is $0.5 \,V$,the current will be.....$ mA$

In the given circuit,the current flowing through the ideal $P-N$ junction diode is .......$mA$.

When a forward bias is applied to a $p-n$ junction,it $\qquad$ .

$A$ circuit is arranged as shown in the figure. The output voltage ${V}_{0}$ is equal to $\ldots \ldots \text{ V}$.

$A$ diode is connected to $220 \, V \, (rms) \, ac$ in series with a capacitor as shown in the figure. The voltage across the capacitor is

Vedclass Test Series

Exam Paper Generator

Online Exam Module