A spring of force constant K is first stretch | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The work done in stretching a spring by a distance $x$ is given by the potential energy stored,$U = \frac{1}{2} K x^2$.Initial work done to stretc

Vedclass · Accepted Answer

$\frac{1}{2} K b(2 a+b)$

Vedclass · Answer

(C) The work done in stretching a spring by a distance $x$ is given by the potential energy stored,$U = \frac{1}{2} K x^2$.Initial work done to stretch the spring by distance $a$ is $W_1 = \frac{1}{2} K a^2$.Total work done to stretch the spring by a total distance of $(a+b)$ is $W_2 = \frac{1}{2} K (a+b)^2$.The work done in stretching the spring further by distance $b$ is the difference between the total work and the initial work:$\Delta W = W_2 - W_1$$\Delta W = \frac{1}{2} K (a+b)^2 - \frac{1}{2} K a^2$$\Delta W = \frac{1}{2} K (a^2 + 2ab + b^2 - a^2)$$\Delta W = \frac{1}{2} K (2ab + b^2)$$\Delta W = \frac{1}{2} K b(2a + b)$.

$A$ spring of force constant $K$ is first stretched by distance $a$ from its natural length and then further by distance $b$. The work done in stretching the part $b$ is .............

Similar Questions

$A$ block of mass $100 \ g$ moving at a speed of $2 \ m \ s^{-1}$ compresses a spring through a distance $2 \ cm$ before its speed is halved. Find the spring constant of the spring. (in $N \ m^{-1}$)

Is the work done by the stretching force in a stretched spring positive or negative?

In stretching a spring by $2 \, cm$,the energy stored is $U$. If the spring is stretched by an additional $10 \, cm$,the total energy stored will be:

$A$ block of mass $M$ moves on a frictionless horizontal surface and collides with a spring of spring constant $k$. The spring is compressed by a length $L$. What is the maximum momentum of the block after the collision?

$A$ block of mass $M$ moving on a frictionless horizontal surface collides with a spring of spring constant $K$ and compresses it by a length $L$. The maximum momentum of the block during the collision process is

Vedclass Test Series

Exam Paper Generator

Online Exam Module