(D) The Doppler shift in wavelength for a source moving away from the observer is given by $\Delta \lambda = \frac{v}{c} \lambda$.Given: $\lambda = 58

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Increase by $70.75 \ \mathring{A}$

(D) The Doppler shift in wavelength for a source moving away from the observer is given by $\Delta \lambda = \frac{v}{c} \lambda$.Given: $\lambda = 5896 \ \mathring{A}$,$v = 3600 \ km/s = 3.6 \times 10^6 \ m/s$,and $c = 3 \times 10^8 \ m/s$.Substituting the values: $\Delta \lambda = \frac{3.6 \times 10^6}{3 \times 10^8} \times 5896$.$\Delta \lambda = 1.2 \times 10^{-2} \times 5896 = 70.752 \ \mathring{A}$.Since the star is moving away,the observed wavelength increases. Thus,the wavelength increases by $70.75 \ \mathring{A}$.

Class 12 Physics Wave Optics Doppler's Effect of Light

Medium

$A$ star emitting light of wavelength $5896 \ \mathring{A}$ is moving away from the earth with a speed of $3600 \ km/s$. The wavelength of light observed on earth will be:
($c = 3 \times 10^8 \ m/s$ is the speed of light)

A
Decrease by $5825.25 \ \mathring{A}$
B
Increase by $5966.75 \ \mathring{A}$
C
Decrease by $70.75 \ \mathring{A}$
D
Increase by $70.75 \ \mathring{A}$

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Wave Optics

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Doppler's Effect of Light

The periodic time of rotation of a certain star is $22$ days and its radius is $7 \times 10^8 \ m$. If the wavelength of light emitted by its surface is $4320 \ \mathring{A}$, the Doppler shift will be $(1 \ day = 86400 \ s)$

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The wavelength of light coming from a star is $3700 \, \mathring{A}$. If the observed wavelength from Earth is $3737 \, \mathring{A}$,what is the velocity of the star? [$c = 3 \times 10^8 \, m/s$]

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$A$ star is moving towards the earth with a speed of $4.5 \times 10^6 \ m/s$. If the true wavelength of a certain line in the spectrum received from the star is $5890 \ \mathring A$,its apparent wavelength will be about........$\mathring A$ $[c = 3 \times 10^8 \ m/s]$

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The $6563\,\mathring{A}$ $H_{\alpha}$ line emitted by hydrogen in a star is found to be redshifted by $15\,\mathring{A}$. Estimate the speed with which the star is receding from the Earth.

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$A$ star producing light of wavelength $6000 \ \mathring{A}$ moves away from the Earth with a speed of $5 \ km/s$. Due to the Doppler effect, the shift in wavelength will be $...... \ \mathring{A}$ $(c = 3 \times 10^8 \ m/s)$.

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$A$ star emitting light of wavelength $5896 \ \mathring{A}$ is moving away from the earth with a speed of $3600 \ km/s$. The wavelength of light observed on earth will be:($c = 3 \times 10^8 \ m/s$ is the speed of light)

Similar Questions

The periodic time of rotation of a certain star is $22$ days and its radius is $7 \times 10^8 \ m$. If the wavelength of light emitted by its surface is $4320 \ \mathring{A}$, the Doppler shift will be $(1 \ day = 86400 \ s)$

The wavelength of light coming from a star is $3700 \, \mathring{A}$. If the observed wavelength from Earth is $3737 \, \mathring{A}$,what is the velocity of the star? [$c = 3 \times 10^8 \, m/s$]

$A$ star is moving towards the earth with a speed of $4.5 \times 10^6 \ m/s$. If the true wavelength of a certain line in the spectrum received from the star is $5890 \ \mathring A$,its apparent wavelength will be about........$\mathring A$ $[c = 3 \times 10^8 \ m/s]$

The $6563\,\mathring{A}$ $H_{\alpha}$ line emitted by hydrogen in a star is found to be redshifted by $15\,\mathring{A}$. Estimate the speed with which the star is receding from the Earth.

$A$ star producing light of wavelength $6000 \ \mathring{A}$ moves away from the Earth with a speed of $5 \ km/s$. Due to the Doppler effect, the shift in wavelength will be $...... \ \mathring{A}$ $(c = 3 \times 10^8 \ m/s)$.

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$A$ star emitting light of wavelength $5896 \ \mathring{A}$ is moving away from the earth with a speed of $3600 \ km/s$. The wavelength of light observed on earth will be:
($c = 3 \times 10^8 \ m/s$ is the speed of light)