A steel wire has a magnetic moment M. What wi | vedclass

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(C) Let the length of the steel wire be $l$. The initial magnetic moment is $M = m \cdot l$,where $m$ is the pole strength.Thus,the pole strength is $

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$\frac{2M}{\pi}$

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(C) Let the length of the steel wire be $l$. The initial magnetic moment is $M = m \cdot l$,where $m$ is the pole strength.Thus,the pole strength is $m = \frac{M}{l}$.When the wire is bent into a semi-circular arc of radius $r$,the length of the wire corresponds to the circumference of the semi-circle: $\pi r = l$,which gives $r = \frac{l}{\pi}$.The distance between the two poles (the diameter of the semi-circle) is $d = 2r = \frac{2l}{\pi}$.The new magnetic moment $M'$ is the product of the pole strength and the distance between the poles:$M' = m \cdot (2r) = \left(\frac{M}{l}\right) \cdot \left(\frac{2l}{\pi}\right) = \frac{2M}{\pi}$.

$A$ steel wire has a magnetic moment $M$. What will be its magnetic moment if it is bent into a semi-circular arc?

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