A string of mass 2.5 , kg is under some tensi | vedclass

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(B) The velocity of the transverse wave in the string is given by $v = \frac{L}{t}$,where $L = 20 \, m$ and $t = 0.5 \, s$.$v = \frac{20}{0.5} = 40 \,

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$200$

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(B) The velocity of the transverse wave in the string is given by $v = \frac{L}{t}$,where $L = 20 \, m$ and $t = 0.5 \, s$.$v = \frac{20}{0.5} = 40 \, m/s$.The velocity of a transverse wave in a string is also given by $v = \sqrt{\frac{T}{\mu}}$,where $T$ is the tension and $\mu$ is the linear mass density.Linear mass density $\mu = \frac{m}{L} = \frac{2.5 \, kg}{20 \, m} = 0.125 \, kg/m$.Squaring the velocity formula,we get $v^2 = \frac{T}{\mu}$,which implies $T = v^2 	imes \mu$.Substituting the values: $T = (40)^2 	imes 0.125 = 1600 	imes 0.125 = 200 \, N$.

$A$ string of mass $2.5 \, kg$ is under some tension. The length of the stretched string is $20 \, m$. If the transverse jerk produced at one end of the string takes $0.5 \, s$ to reach the other end,the tension in the string is .... $N$

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