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(B) The power $P$ supplied to the substance to keep it in the molten state at its melting point is equal to the rate at which heat is lost to the surr

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$\frac{Pt}{m}$

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(B) The power $P$ supplied to the substance to keep it in the molten state at its melting point is equal to the rate at which heat is lost to the surroundings to maintain the phase change equilibrium.When the power is turned off,the energy released by the substance as it solidifies is equal to the energy it would have absorbed to melt,which is given by $Q = P 	imes t$.The heat required for the phase change (solidification) is given by $Q = mL$,where $L$ is the latent heat of fusion.Equating the two expressions for energy: $mL = P 	imes t$.Therefore,the latent heat of fusion is $L = \frac{Pt}{m}$.

Column-$I$	Column-$II$
$(a)$ Latent heat of vaporization $L_V$	$(i)$ $22.6 \times 10^5 \, J/kg$
$(b)$ Latent heat of fusion $L_f$	$(ii)$ $33.3 \times 10^5 \, J/kg$
	$(iii)$ $3.33 \times 10^5 \, J/kg$

$A$ substance of mass $m \ kg$ requires a power input of $P \ W$ to remain in the molten state at its melting point. When the power is turned off,the substance completely solidifies in time $t \ s$. The latent heat of fusion of the substance is

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