A sum of ₹ 1000 is invested at 8 % simple int | vedclass

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(C) The formula for simple interest is $	ext{Simple Interest} = \frac{P 	imes R 	imes T}{100}$.Interest at the end of the $1^{st}$ year $= \frac{10

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$2400$

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(C) The formula for simple interest is $	ext{Simple Interest} = \frac{P 	imes R 	imes T}{100}$.Interest at the end of the $1^{st}$ year $= \frac{1000 	imes 8 	imes 1}{100} = ₹ 80$.Interest at the end of the $2^{nd}$ year $= \frac{1000 	imes 8 	imes 2}{100} = ₹ 160$.Interest at the end of the $3^{rd}$ year $= \frac{1000 	imes 8 	imes 3}{100} = ₹ 240$.The sequence of interests is $80, 160, 240, \dots$.Since the difference between consecutive terms is constant $(d = 80)$,this sequence forms an $AP$ with first term $a = 80$ and common difference $d = 80$.To find the interest at the end of $30 	ext{ years}$,we calculate the $30^{th}$ term $(a_{30})$:$a_{30} = a + (30 - 1)d = 80 + 29 	imes 80 = 80 + 2320 = 2400$.Thus,the interest at the end of $30 	ext{ years}$ is ₹ $2400$.

$A$ sum of ₹ $1000$ is invested at $8 \%$ simple interest per year. Calculate the interest at the end of each year. Do these interests form an $AP$? If so,find the interest at the end of $30 \text{ years}$ making use of this fact. (in ₹)

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