A swimmer dived off a cliff with a running ho | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The swimmer performs horizontal projectile motion.Let $h = 10 \ m$ be the vertical height and $x = 2 \ m$ be the horizontal distance to clear.The

Vedclass · Accepted Answer

$1.4$

Vedclass · Answer

(B) The swimmer performs horizontal projectile motion.Let $h = 10 \ m$ be the vertical height and $x = 2 \ m$ be the horizontal distance to clear.The time taken to fall $10 \ m$ is given by $h = \frac{1}{2} g t^2$.Using $g = 9.8 \ m/s^2$,we get $t = \sqrt{\frac{2h}{g}} = \sqrt{\frac{2 	imes 10}{9.8}} = \sqrt{2.04} \approx 1.428 \ s$.To clear the ledge,the horizontal distance covered must be at least $2 \ m$.Using $x = v 	imes t$,we have $v = \frac{x}{t} = \frac{2}{1.428} \approx 1.4 \ m/s$.Thus,the minimum speed required is $1.4 \ m/s$.

$A$ swimmer dived off a cliff with a running horizontal leap. What must his minimum speed be just as he leaves the top of the cliff so that he will miss the edge at the bottom,given that the ledge at the bottom is $2 \ m$ wide and $10 \ m$ below the top of the cliff?

Similar Questions

$A$ projectile is projected at $10 \ m/s$ by making an angle of $60^{\circ}$ to the horizontal. After some time,its velocity makes an angle of $30^{\circ}$ to the horizontal. Its speed at this instant is:

$A$ ball rolls from the top of a stairway with a horizontal velocity $u \; m/s$. If the steps are $h \; m$ high and $b \; m$ wide,the ball will hit the edge of the $n^{th}$ step,if $n=$

The height $y$ and the distance $x$ along the horizontal plane of a projectile on a certain planet (with no surrounding atmosphere) are given by $y = (8t - 5t^2) \ m$ and $x = 6t \ m$,where $t$ is in seconds. The velocity with which the projectile is projected is ......... $m/s$.

Two guns $A$ and $B$ can fire bullets at speeds $1 \ km/s$ and $2 \ km/s$ respectively. From a point on a horizontal ground,they are fired in all possible directions. The ratio of the maximum areas covered by the bullets fired by the two guns on the ground is

The equation of a projectile is $y = ax - bx^2$. Its horizontal range is ......

Vedclass Test Series

Exam Paper Generator

Online Exam Module