(B) The potential at any point on a conducting shell is the same as the potential at its center due to all charges present in the system.Potential $V

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(B) The potential at any point on a conducting shell is the same as the potential at its center due to all charges present in the system.Potential $V = V_{\text{shell}} + V_A + V_B + V_C$$V = \frac{KQ_0}{R} + \frac{KQ_0}{R/2} + \frac{K(-2Q_0)}{2R/3} + \frac{K(3Q_0)}{2R}$$V = \frac{KQ_0}{R} + \frac{2KQ_0}{R} - \frac{3KQ_0}{R} + \frac{1.5KQ_0}{R}$$V = \frac{1.5KQ_0}{R} = \frac{3KQ_0}{2R}$

Class 12 Physics Electrostatic Potential and Capacitance Electric potential

Medium

$A$ thin conducting spherical shell (center at $O$) having charge $Q_0$,radius $R$ and three point charges $Q_0$,$-2Q_0$,$3Q_0$ are kept at points $A$,$B$,and $C$ respectively as shown in the figure. Find the potential at any point on the conducting shell. (Potential at infinity is assumed to be zero)

A
$\frac{5KQ_0}{2R}$
B
$\frac{3KQ_0}{2R}$
C
$\frac{KQ_0}{3R}$
D
None of these

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Class 12

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Electrostatic Potential and Capacitance

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Electric potential

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Along the $x$-axis,three charges $\frac{q}{2}, -q$ and $\frac{q}{2}$ are placed at $x=0, x=a$ and $x=2a$ respectively. The resultant electric potential at a point $P$ located at a distance $r$ from the charge $-q$ $(r > a)$ is ($\varepsilon_0$ is the permittivity of free space):

DifficultAP EAMCET 2006

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Two point charges $q_1$ and $q_2$ are separated by a distance $d$. What is the increase in potential energy of the system when $q_2$ is moved towards $q_1$ by a distance $x$? $(x < d)$ (where $\frac{1}{4 \pi \varepsilon_0} = K$ is a constant).

DifficultMHT CET 2023

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$A$ hollow charged metal sphere has radius $R$. If the potential difference between its surface and a point at a distance $5R$ from the centre is $V$,then the magnitude of the electric field intensity at a distance $5R$ from the centre of the sphere is:

EasyMHT CET 2021

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$A$ charge $+q$ is distributed over a thin ring of radius $r$ with line charge density $\lambda = q \sin^2 \theta / (\pi r)$. Note that the ring is in the $XY$-plane and $\theta$ is the angle made by the position vector with the $X$-axis. The work done by the electric force in displacing a point charge $+Q$ from the centre of the ring to infinity is

MediumKVPY 2019

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Choose the $CORRECT$ option.

Along the $x$-axis,three charges $\frac{q}{2}, -q$ and $\frac{q}{2}$ are placed at $x=0, x=a$ and $x=2a$ respectively. The resultant electric potential at a point $P$ located at a distance $r$ from the charge $-q$ $(r > a)$ is ($\varepsilon_0$ is the permittivity of free space):

Two point charges $q_1$ and $q_2$ are separated by a distance $d$. What is the increase in potential energy of the system when $q_2$ is moved towards $q_1$ by a distance $x$? $(x < d)$ (where $\frac{1}{4 \pi \varepsilon_0} = K$ is a constant).

$A$ hollow charged metal sphere has radius $R$. If the potential difference between its surface and a point at a distance $5R$ from the centre is $V$,then the magnitude of the electric field intensity at a distance $5R$ from the centre of the sphere is:

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