A tower stands vertically inside an acute-ang | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let the height of the tower be $h$ and its distances from the vertices $P, Q,$ and $R$ be $d_1, d_2,$ and $d_3$ respectively.Let the angle of elev

Vedclass · Accepted Answer

circumcentre

Vedclass · Answer

(B) Let the height of the tower be $h$ and its distances from the vertices $P, Q,$ and $R$ be $d_1, d_2,$ and $d_3$ respectively.Let the angle of elevation from each corner be $	heta$.Then,$	an(	heta) = \frac{h}{d_1} = \frac{h}{d_2} = \frac{h}{d_3}$.This implies $d_1 = d_2 = d_3$.The point that is equidistant from all the vertices of a triangle is the circumcentre of the triangle.Therefore,the foot of the tower is at the circumcentre.

$A$ tower stands vertically inside an acute-angled triangular park $\Delta PQR$. If the angle of elevation of the top of the tower from each corner of the park is the same,then in $\Delta PQR$,the foot of the tower is at the

Similar Questions

The circumcentre of a triangle formed by the lines $xy + 2x + 2y + 4 = 0$ and $x + y + 2 = 0$ is

If $(a, b - c)$,$(b, c - a)$,and $(c, a - b)$ are the vertices of a triangle,then where does the centroid of the triangle lie?

The orthocentre of the triangle formed by the lines $xy = 0$ and $x + y = 1$ is

The vertices of a triangle are at $-\hat{i}+3 \hat{j}$ and $2 \hat{i}+5 \hat{j}$ and its orthocenter is at $\hat{i}+2 \hat{j}$. If the position vector of the third vertex is $a \hat{i}+b \hat{j}$,then $(a, b)=$

If $(-4, 6), (2, 3)$ and $(-2, -5)$ are the vertices of a triangle,find its incenter.

Vedclass Test Series

Exam Paper Generator

Online Exam Module