A toy is in the form of a cone of radius 3.5 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) It can be observed that the radius of the conical part and the hemispherical part is the same (i.e.,$r = 3.5 \, cm = \frac{7}{2} \, cm$).Height of

Vedclass · Accepted Answer

$214.5$

Vedclass · Answer

(C) It can be observed that the radius of the conical part and the hemispherical part is the same (i.e.,$r = 3.5 \, cm = \frac{7}{2} \, cm$).Height of the hemispherical part = Radius $(r) = 3.5 \, cm = \frac{7}{2} \, cm$.Height of the conical part $(h) = 15.5 \, cm - 3.5 \, cm = 12 \, cm$.Slant height $(l)$ of the conical part is given by $l = \sqrt{r^2 + h^2}$.$l = \sqrt{\left( \frac{7}{2} ight)^2 + (12)^2} = \sqrt{\frac{49}{4} + 144} = \sqrt{\frac{49 + 576}{4}} = \sqrt{\frac{625}{4}} = \frac{25}{2} \, cm = 12.5 \, cm$.Total surface area of the toy = $CSA$ of the conical part + $CSA$ of the hemispherical part.Total surface area = $\pi r l + 2 \pi r^2 = \pi r (l + 2r)$.Total surface area = $\frac{22}{7} 	imes \frac{7}{2} 	imes \left( 12.5 + 2 	imes 3.5 ight) = 11 	imes (12.5 + 7) = 11 	imes 19.5 = 214.5 \, cm^2$.

$A$ toy is in the form of a cone of radius $3.5 \, cm$ mounted on a hemisphere of the same radius. The total height of the toy is $15.5 \, cm$. Find the total surface area of the toy (in $cm^2$). $\left[ \text{Use } \pi = \frac{22}{7} \right]$

Similar Questions

$A$ cone of maximum size is carved out from a cube of edge $14 \, cm$. Find the surface area of the cone and the surface area of the remaining solid left after the cone is carved out.

The formula for finding the total surface area of a cylinder having cone-shaped lids at both the ends will be $\ldots \ldots \ldots \ldots$

$TSA$ of a cone with radius $4\, cm$ and height $3\, cm$ is $\ldots \ldots \ldots \ldots cm^{2}$. (in $\pi$)

The $CSA$ (Curved Surface Area) of a $1-$ rupee coin is given by the formula $\ldots \ldots \ldots \ldots .$

Total surface area of a cube open at one end $= \dots$

Vedclass Test Series

Exam Paper Generator

Online Exam Module