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(A) $1$. The first train starts at $9\, am$ and travels for $2$ hours until the second train starts at $11\, am$.$2$. Distance covered by the first tr

Vedclass · Accepted Answer

$150$

Vedclass · Answer

(A) $1$. The first train starts at $9\, am$ and travels for $2$ hours until the second train starts at $11\, am$.$2$. Distance covered by the first train in $2$ hours $= 50\, km/h 	imes 2\, h = 100\, km$.$3$. Remaining distance between the two trains at $11\, am = 210\, km - 100\, km = 110\, km$.$4$. Since the trains are moving towards each other,their relative speed $= 50\, km/h + 60\, km/h = 110\, km/h$.$5$. Time taken to meet after $11\, am = \frac{	ext{Remaining Distance}}{	ext{Relative Speed}} = \frac{110\, km}{110\, km/h} = 1\, hour$.$6$. The trains meet at $12\, pm$ (noon).$7$. Total distance from station $A$ at the meeting point = (Distance covered by first train in $2$ hours) + (Distance covered by first train in $1$ hour after $11\, am$) = $100\, km + (50\, km/h 	imes 1\, h) = 150\, km$.

$A$ train starts from station $A$ at $9\, am$ and travels at $50\, km/h$ towards station $B,$ which is $210\, km$ away. Another train starts from station $B$ at $11\, am$ and travels at $60\, km/h$ towards station $A.$ At what distance from station $A$ will they meet? (in $km$)

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