$A$ transistor connected in common emitter mode has a load resistance of $5 \, k\Omega$. If the input peak voltage is $5 \, mV$ and the current gain $(\beta)$ is $50$, find the voltage gain.

In an $NPN$ transistor,$10^{10}$ electrons enter the emitter in $10^{-6} \ s$ and $2\%$ of the electrons recombine with holes in the base. The current gains $\alpha$ and $\beta$ are respectively:

In common emitter mode of a transistor, the current gain is $8$. The input impedance is $25 \, k\Omega$ and load resistance is $75 \, k\Omega$. The power gain is

Which region is the least doped in a transistor?

In a common emitter $(CE)$ amplifier having a voltage gain $G,$ the transistor used has transconductance $0.03\, mho$ and current gain $25.$ If the above transistor is replaced with another one with transconductance $0.02\, mho$ and current gain $20,$ the voltage gain will be

For a common emitter configuration,if $\alpha$ and $\beta$ have their usual meanings,the incorrect relation between $\alpha$ and $\beta$ is